Answer:-
To graph the linear inequality 2 ???? − 3 ???? ≤ 12 2x−3y≤12, first, convert it to an equation: 2 ???? − 3 ???? = 12 2x−3y=12. Plot the line by finding intercepts. For ???? = 0 x=0, ???? = − 4 y=−4 (point ( 0 , − 4 ) (0,−4)); for ???? = 0 y=0, ???? = 6 x=6 (point ( 6 , 0 ) (6,0)). Draw a solid line through these points because the inequality includes "equal to." Next, shade the region below the line since 2 ???? − 3 ???? ≤ 12 2x−3y≤12. Test a point like ( 0 , 0 ) (0,0): 2 ( 0 ) − 3 ( 0 ) ≤ 12 2(0)−3(0)≤12 is true, confirming the shaded area.
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